Question

2sin theta = root 3cos10 + sin10
Please please ans

Answer 1

Answer:

2 sin theta = root 3 cos 10 + sin 10

gives

70 degrees

Answer 2

The value of θ is 70°.

Given,

A trigonometric equation 2sin θ = √3cos10 + sin10.

To Find,

The value of this θ.

Solution,

The given expression is

2sin θ = √3cos10 + sin10

sin θ = √3/2cos10 + 1/2sin10

Now, we know that

sin 60 = √3/2

cos 60 = 1/2

Now, substituting the values

sin θ = sin60*cos10+cos60*sin10

sin θ = sin (60+10) ( sin(a+b) = sina*cosb + cosa*sinb )

sin θ = sin 70

θ = 70°

Hence, the value of θ is 70°.

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