Math, asked by poojagadtia, 7 months ago

2sin180/32=√2+√2+√2+√2+√2 solve it

Answers

Answered by manishrajput72

0

Answer:

2sin180/32 = √2+√2+√2+√2+√2

2(0) / 32 = 5√2 ( sin180 = 0 )

0 = 5√2

0=1

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