Question

2sin²30tan60-3cos²60sec²30

solve please​

Answer 1

Answer:

We know that tan60=cot30 2si

sin^230cot30=2sin30cos30=sin60 =3^1/2 ÷2

3cos60cos60sec30sec30=3×1/4×4/3

2sin² 30tan60-3cos² 60sec²30= 3^1/2 ÷2 -1

Answer 2

Answer:

hlo mate here is ur answer

Step-by-step explanation:

we know that

tan69=cot30

sin^230cot 30=2sin30 cos 30=sin60

=3^1/2÷2

3cos 60cos 60sec30sec30=3×1/4×4/3

2sin 30tan 60-3cos2 60sec2 30 =3^1/2÷2-1

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