2sin²A+cos⁴A=1+sin⁴A
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Answer:
Step-by-step explanation:
2sin^2A+cos^4A
=2sin^2A+cos^2A.cos^2A
=2sin^2A+(1-sin^2A)(1-sin^2A)
=2sin^2A+(1-sin^2A-sin^2A+sin^4A)
=2sin^2A+1-2sin^2A+sin^4A
=1+sin^4A
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Answer:
solved
Step-by-step explanation:
2sin²A+cos⁴A=1+sin⁴A
LHS = 2sin²A+cos⁴A = 2sin²A+( 1 - sin²A)² = 2sin²A+ 1 - 2sin²A + sin⁴A
= 1+sin⁴A = RHS
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