Math, asked by devikasanthosh416, 6 hours ago

2sin²B - cos²B = 2 , the B = ?
please provide complete answer step wise

Answers

Answered by veenasehdev3449

1

Answer:

[Taking RHS:

cos(A−B)[cos(A−B)−2cosA.cosB]+cos2B

=cos(A−B)[cosA.cosB+sinA.sinB−2cosA.cosB]+cos2B

=−cos(A−B).cos(A+B)+cos2B

=cos2B−22cos(A−B)cos(A+B)

=21[2cos2B−cos2A−cos2B]

=21[2sin2A]=sin2A[/tex]

Step-by-step explanation:

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