Question

2sin²theta+cos²theta=​

Answer 1

Answer:

Step-by-step explanation:

\begin{gathered}2 { \sin( \alpha ) }^{2} - { \cos( \alpha ) }^{2} = 2 \\ put \: cos { \alpha }^{2} = 1 - \sin( { \alpha }^{2} ) \\ 2 { \sin( \alpha ) }^{2} - (1 - { \sin( \alpha )) }^{2} = 2 \\ 3 \sin( {\alpha }^{2} ) = 3 \\ \sin( { \alpha }^{2} ) = 1 \\ \sin( \alpha ) = + - 1 \\ \alpha = + - \pi \div 2\end{gathered}

2sin(α)

2

−cos(α)

2

=2

putcosα

2

=1−sin(α

2

)

2sin(α)

2

−(1−sin(α))

2

=2

3sin(α

2

)=3

sin(α

2

)=1

sin(α)=+−1

α=+−π÷2