Math, asked by praveenkumar2433, 1 year ago

2sin²x +1=3sinx equation for solutions

Answers

Answered by Iamkeetarp
1
2sin^2x - 3sinx + 1 = 0

2sin^2x - 2sinx - sinx + 1 = 0

2sinx(sinx - 1 ) -1 (sinx - 1) = 0

(2sinx - 1)(sinx-1) = 0

sinx = 1/2 , x = 30°

sinx = 1 , x = 90°

Hope it helped you...
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