Question

(2sin3A.cosA)/(2cos3A.sinA)=​

Answer 1

refer to the attachment hope it helps you

Answer 2

Answer:

Tan3A.cotA

Step-by-step explanation:

As we have given in the question we need to divide the given trigonometric functions. The question is very easy all we have to do is just divide by the same angle and we should also know the trigonometric identities and functions. As we know

$\dfrac{sin}{cos}=tan$ and $\dfrac{cos}{sin}=cot$

We have given that $\dfrac{2sin3A.cosA}{2cos3A.sinA}$

So 2/2 will cancel directly and by functions, The division will change in tan and cot but the angle must be the same.

Therefore our final answer would be as follows

$\dfrac{sin3A.cosA}{cos3A.sinA}=tan3A.cotA$