Math, asked by jgxti, 1 year ago

2sin3@=underoot 3 find value of @

Answers

Answered by GarvitaTalwar
1
2sin3a = \sqrt{3 } \\ \ = > \sin3a = \sqrt{3} \div 2 \\ \ = > \sin3a = \sin60 \\ = > 3a = 60 \\ \ \ = > a = 20
threrefore
a=20
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