Question

2sin41 sec49 - tan35 tan55 + 2cosec^2 30

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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$\frak\red{Question}\:❓ \\ 2sin41 sec49 - tan35 tan55 + 2cosec^2 30 \\ = 2 \sin(90 - 49) \sec(49) - \tan(90 - 55) \tan(55) + 2 \csc {}^{2} (30) \\ = 2 \cos(49) \times \frac{1}{ \cos(49) } - \cot(55) \times \frac{1}{ \cot(55) } + 2 \times {2}^{2} \\ = 2 - 1 + 8 \\ = 9 \: \: \: \: \frak\red {answer}\:$