(2sin4xcos4x)(2sin2xcos2x) is equal to
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we have,
2sinФcosФ = sin2Ф
so 2sin4xcos4x = sin8x
2sin4xcos4x = sin4x
∴ (2sin4xcos4x)( 2sin4xcos4x) = sin4xsin8x
2sinФcosФ = sin2Ф
so 2sin4xcos4x = sin8x
2sin4xcos4x = sin4x
∴ (2sin4xcos4x)( 2sin4xcos4x) = sin4xsin8x
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