2sin5x × cosx × 2cos5x × sinx=?
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Answered by
1
Step-by-step explanation:
hi id you give option i can easily say your answer
actually we can keep x as0 and substitute you will get 0 if you keep x as pi^2 you wil get 0 hence i think the answer is zero
further reference
cos 0=1
sin 0=0
cos 90=0
cos 0=1
Answered by
1
Answer:
brother sorry for the inconvenience I don't want to spam your que but try to helpme out I am stucked
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