Question

2sin81/cos9—tan40/cot50​

Answer 1

Answer:

2sin81/cos9 - tan40/cot50

= 2(sin(90-9)/cos9) - tan(90-50)/cot50

= 2(cos9/cos9) - cot50/cot50

= 2(1) - 1

= 2 - 1

=1

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