2sinA-3cosA = 2
(0⁰≤A≤90⁰)
, find the value of A
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Step-by-step explanation:
tan ф = 4/3
(2 sin ф - 3 cos ф)/(2 sin ф + 3 cos ф) =
[(2 sin ф - 3 cos ф) * (1/cos ф)] / [(2 sin ф + 3 cos ф) * (1/cos ф)] =
(2 sin ф/cos ф - 3 cos ф/cos ф)/(2 sin ф/cos ф + 3 cos ф/cos ф) =
(2 tan ф - 3)/(2 tan ф + 3) =
(2 * 4/3 - 3)/(2 * 4/3 + 3) = [(8 - 9)/3] / [(8 + 9)/3] = -1/17
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