Question

2sina*cosa-cosa/1-sina+sin2a-cos2a=cota.

Answer 1

Answer:

(2sinA.cosA-cosA)/(1-sinA+sin^2A-cos^2A) = cot A.

L.H.S.

= cosA.(2sinA-1)/{(1-cos^2A)+sin^2A-sinA}. , putting 1-cos^2A = sin^2A.

= cosA.(2sinA-1)/{sin^2A+sin^2A-sinA}.

= cosA.(2.sinA-1)/{2.sin^2A-sinA}.

= cosA.(2sinA-1)/sinA.(2.sinA-1).

= cosA/sinA.

= cotA. Proved.