Question

2sinA.cosA ( full fromula with example)

Answer 1

$sin2a = sina.cosa + sina.cosa = 2sina.cosa$ =sin(a+a)

Answer 2

hello user !!

Here's your answer :

___________________

•There's no formula for 2sinA.cosA , but it is for 2sinA.cosB.

•Please refer the image attached above. The example too is provided.

________________________

Thank you. Doubts are most welcome :)