2sinAsinB=cos (A-B)-cos (A+B)
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Answered by
16
cos(A-B)=cosAcosB+sinA+sinB
and
cos(A+B)=cosAcosB-sinAsinB
cos(A-B)-cos(A+B)=cosAcosB+sinAsinB-(cosAcosB-sinAsinB)
=cosAcosB+sinAsinB-cosAcosB+sinAsinB
=2sinAsinB
Hence Proved...
Hope it hepled you!! :)
and
cos(A+B)=cosAcosB-sinAsinB
cos(A-B)-cos(A+B)=cosAcosB+sinAsinB-(cosAcosB-sinAsinB)
=cosAcosB+sinAsinB-cosAcosB+sinAsinB
=2sinAsinB
Hence Proved...
Hope it hepled you!! :)
Answered by
0
Answer:
2sinAcosB
Step-by-step explanation:
it will help u
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