Question

2sinx=1,432 mathematics equation

Answer 1

Answer:

The sine function is often defined by its Taylor series around [math]0[/math] (If you are not familiar with this, a Taylor series is basically a polynomial of infinite degree).

We can therefore write [math]2\sin(x)=2\sum_{n=0}^\infty \frac{(-1)^nx^{2n+1}}{(2n+1)!} = \sum_{n=0}^\infty 2\frac{(-1)^nx^{2n+1}}{(2n+1)!} = \frac{2x}{1!} - \frac{2x^3}{3!} + \frac{2x^5}{5!} - \ldots[/math]

Step-by-step explanation:

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