Math, asked by wananum, 2 months ago

2sinx/2cosx-secx=tan2x​

Answers

Answered by patil28kalyani
1

Step-by-step explanation:

2sinx/(2cosx-secx)

=2sinx/(2cosx- 1/cosx) As secx=1/cosx

Multiplying both the numerator and denominator by cos x,

We get 2sinxcosx/ (2cos^2x -1)

Since 2sinxcosx=sin2x and 2cos^2x -1=cos2x

2sinxcosx/(2cos^2x-1)= sin2x/cos2x = tan2x

hope you got it

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