2sinx/2cosx-secx=tan2x
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Step-by-step explanation:
2sinx/(2cosx-secx)
=2sinx/(2cosx- 1/cosx) As secx=1/cosx
Multiplying both the numerator and denominator by cos x,
We get 2sinxcosx/ (2cos^2x -1)
Since 2sinxcosx=sin2x and 2cos^2x -1=cos2x
2sinxcosx/(2cos^2x-1)= sin2x/cos2x = tan2x
hope you got it
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