2sinx+5cosy+7sinz=14 then 7tanx/2+4cosy-6cosz
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Given equation is only possible if
Sin x = cos y = sin Z = 1 ;
x = Z = π/2, y = 0 ;
Thus putting them on 2nd equation, result is 11
Sin x = cos y = sin Z = 1 ;
x = Z = π/2, y = 0 ;
Thus putting them on 2nd equation, result is 11
Mahedarreddy:
very nice thank you so much
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Step-by-step explanation:
guys the first pic is in reverse so pls check it properly....
thank uu
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