Question

2sinx-sin2x/xcube xtends to 0​

Answer 1

Using sin2x = 2sinxcosx

$= \frac{2sin \: x(1 - cos \: x)}{x \: x {}^{2} } \\ = \frac{2.2sin {}^{2} \frac{x}{2}}{ \frac{x {}^{2} }{4} 4} \\ = 1$