2sinxcosx=1 then sinx-cosx=?
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(sinx - cosx)² = sin²x + cos²x - 2sinxcosx
=>(sinx - cosx)² = 1 - 2sinxcosx
From the question,
(sinx - cosx)² = 2sinxcosx - 2sinxcosx = 0
=>sinx - cosx = sq. root of 0= 0.
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=>(sinx - cosx)² = 1 - 2sinxcosx
From the question,
(sinx - cosx)² = 2sinxcosx - 2sinxcosx = 0
=>sinx - cosx = sq. root of 0= 0.
Hope this will help you.
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
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