Question

2small3root4+7small3root32-small3root500​

Answer 1

Answer:

$\huge\underline\bold\red{AnswEr}$

$Given : Expression 2\sqrt[3]{4}+7\sqrt[3]{32}-\sqrt[3]{500}$

To find : Simplify the expression ?

Solution :

$Expression 2\sqrt[3]{4}+7\sqrt[3]{32}-\sqrt[3]{500}$

where values can be written as,

$32=2\times 2\times 2\times 2\times 2$

i.e. $\sqrt[3]{32}=2\times \sqrt[3]{4}$

$500=4\times 5\times 5\times 5$

i.e. $\sqrt[3]{500}=5\times \sqrt[3]{4}$

Substitute in the equation,

$=2\sqrt[3]{4}+7(2\sqrt[3]{4})-5\sqrt[3]{4}$

$=2\sqrt[3]{4}+14\sqrt[3]{4}-5\sqrt[3]{4}$

$=\sqrt[3]{4}(2+14-5)$

$=11\sqrt[3]{4}$

$Therefore, 2\sqrt[3]{4}+7\sqrt[3]{32}-\sqrt[3]{500}=11\sqrt[3]{4}$

Answer 2

Answer:

Hello mate ☺️

$2 \sqrt[3]{4} + 7 \sqrt[3]{32} - \sqrt[3]{50}$

$2 \sqrt[ 3]{4} + 7( 2 \sqrt[3]{4} ) - 5 \sqrt[3]{4}$

$\sqrt[3]{4} (2 + </strong><strong>1</strong><strong>4</strong><strong> - 5)$

$\sqrt[3]{4} \times 4$

$4 \sqrt[3]{4}$

$Hope\:this\:help\:you$