Math, asked by tionshi6, 7 months ago

2square root 6 - square root 6 is equal to ​

Answers

Answered by BATHILLS
5

Answer:

\sqrt[2.44948974278]{6}

Square root of 6 = 2.44948974278

Step-by-step explanation:

Square root of 6 can be easily found by using any of the methods to solve square roots. These methods can either be prime factorization or long division. To find out what is the square root of 6, we just need to be aware of a few solutions and methods.

To find Root 6 one can refer to the methods of simplifying square roots. To simplify a square root, the number should be made as small as possible while still keeping it as a whole number. Mathematically this can be written as:

√a.b = √a * √b

To write this equation for the square root of 6 simplification, we will get:

√6= √2 * √3

This can be further simplified by substituting the values of root 2 and 3 (rounded to three decimal numbers) as:

√6 = 1.414 * 1.732

√6 = 2.449

Thus, this is the simplified version of the square root of 6. Similarly, we can also find square roots of any other whole numbers and find out their factors. After finding the factors, we usually convert them into the lowest divisible number, as we have done above. Thus, we have found the value of root 6. This method is the most popularly used method for finding square roots of any number. Apart from this, if we use a calculator we can find the exact value of this as well. The exact value will always be a decimal number as it is nearly impossible to find a positive whole integer as a root for non-rational numbers.

Another simplistic example of how roots work with one another is by figuring out the Square root of 6 plus square root of 6, and this is an interesting problem with a simplistic solution. Let us see this problem and its solution mathematically,

Sqrt (6) + Sqrt (6) = √6 + √6

√6 + √6 = 2√6

Thus, by substituting the value of root 6, we can find the required answer. Keeping this in mind, we can add these roots together to find the solution to the problem while keeping the base root under the radical sign constant. Hence, in this method, we can find solutions to such problems.

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