Question

(2t+1) is the factor of the polynomial p(t)=4t3+4t2+t+1

Answer 1

Answer:

(2t + 1) is not a factor of p(t)

Step-by-step explanation:

p(t) = 4t³ + 4t² + t + 1

= 2t + 1 = 0

2t = -1

t = -1/2

put t in p(t)

p(t) = 4t³ + 4t² + t + 1

p(-1/2) = 4(-1/2)³ + 4(-1/2)² + (-1/2) + 1

= 4(-1/8) + 4(1/4) -1/2 + 1

= -4/8 + 4/4 - 1/2 + 1

= -1/2 + 1 - 1/2 + 1

= (-1 + 2 - 1 + 2)/2

= ( 4 - 2)/2

= 2/2

= 1