2t ^2 -4t +t-2. Factorise it...
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Answer:
We have t
2
−2t+1 = (t)
2
−2(t)(1)+(1)
2
We know that a
2
−2ab+b
2
=(a−b)
2
Here a=t and b=1
Therefore, t
2
−2t+1=(t)
2
−2(t)(1)+(1)
2
= (t−1)
2
=(t−1)(t−1)
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