Math, asked by shrey200016, 4 months ago

2t^2+5t-12 factorise

please solve this...​

Answers

Answered by imRohitPatil
2

Answer:

2t^2 +5t-12

2t^2 +8t-3t -12

2t(t+4) -3(t+4)

(t+4)(2t-3)

Answered by Anonymous
74

Question :-

Factorize -

\sf 2t^2 + 5t - 12

Answer :

By using the middle term splitting method -

\sf 2t^2 + 5t - 12

\sf = 2t^2 + 8t - 3t - 12

\sf = 2 ( t^2 + 4t ) - 3( t + 4)

\sf = 2t ( t + 4 ) - 3(t + 4)

\sf = ( 2t - 3)(t + 4)

\boxed{\sf 2t^2 + 5t - 12 = (2t - 3)(t+4)}

Additional information :-

Types of Factorization -

(a) Factorization by taking out the common factor :-

When each term of an expression has a common factor, divide each term by this factor and take out as a multiple.

(b) Factorization by grouping

(c) Factorization by making a prefect square

(d) Factorization the difference of two squares.

(e) Factorization of a quadratic polynomial by splitting the middle term.

\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identity}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\sf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\sf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\sf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) + B^{3}\\\\8)\sf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\\end{minipage}}

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