(2t+5)/3 = 3t-10
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Answers
Answered by
1
Step-by-step explanation:
Subtract
3
3t
3t
from both sides of the equation
2
+
5
3
=
3
−
1
0
\frac{2t+5}{3}=3t-10
32t+5=3t−10
2
+
5
3
−
3
=
3
−
1
0
−
3
\frac{2t+5}{3}{\color{#c92786}{-3t}}=3t-10{\color{#c92786}{-3t}}
32t+5−3t=3t−10−3t
2
Simplify
Find common denominator
Combine fractions with common denominator
Multiply the numbers
Combine like terms
Combine like terms
−
7
+
5
3
=
−
1
0
\frac{-7t+5}{3}=-10
3−7t+5=−10
3
Multiply all terms by the same value to eliminate fraction denominators
−
7
+
5
3
=
−
1
0
\frac{-7t+5}{3}=-10
3−7t+5=−10
3
(
−
7
+
5
3
)
Answered by
3
Answer:
(2t+5)/3=3t-10
=> 2t+5= 9t-30
=> -7t= -35
=> t = 5
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