Question

2t-t =21+3(2t+1) solve the t​

Answer 1

Step-by-step explanation:

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Answer 2

Given :-

$\sf 2t - t = 21 + 3(2t + 1)$

Solution :-

→ $\sf 2t - t = 21 + 6t + 3$

→$\sf2t - t - 6t = 21 + 3$

→ $\sf - 5t = 24$

→$\sf t = \dfrac{-24}{5}$

Procedure :-

→ This Question is from the linear equation.

→ Then we can see the there is a bracket after 21+3(2t+1) we will multiply 3 with (2t+1) and then we will get 6t+3 then we will group like terms i.e. 2t - t -6t = 21 + 3. The 6t will become -6t because whenever we transpose any constant it's sign changes.

→ The we will subract 2t - t - 6t and add 21 + 3. You can see that after 2t it's written only t then will consider it as 1, because whenever only a variable is given we consider it as 1.

→ The we have to find the value of t we will take -5 to the R.H.S side then we will make it a fraction, then the final will be -24/5.

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