Question

2t²-t-10 factorise the following polynomial.​

Answer 1

Given :

Polynomial -> 2t^2 - t - 10

To find :

We have to the given polynomial .

Solution :

Let p ( t ) = 2t^2 - t - 10

Now ,

    p ( t ) = 2t^2 - t - 10

=> p ( t ) = 2t^2 + 4t - 5t - 10

=> p ( t ) = 2t * ( t + 2 ) - 5 * ( t + 2 )

=> p ( t ) = ( 2t - 5 ) * ( t + 2 )

( 2t - 5 ) * ( t + 2 ) is the factorise form of the polynomial 2t^2 - t - 10 .

Answer 2

Step-by-step explanation:

Given that:

$2 {t}^{2} - t - 10$

To find: Factors of given polynomial

Solution: Split the middle term,so that it's multiplication is equal to -20

Thus,

$2 {t}^{2} - t - 10 \\ \\ 2 {t}^{2} - 5t + 4t - 10 \\ \\ t(2t - 5) + 2(t - 5) \\ \\ (t +2)(2t - 5) \\ \\ \bold{2 {t}^{2} - t - 10 = (t +2)(2t - 5)}$

Hope it helps you.