2tan^-1(1/2)+sin^-1(3/5)=
Answers
Answered by
1
Answer:
Step-by-step explanation:
2tan^-1(1/2)+sin^-1(3/5)
=tan^-1(1/2)+tan^-1(1/2)+sin^-1(3/5)
=tan^-1(1/2+1/2)/(1–1/2×1/2) + tan^-1(3/4)
=tan^-1(4/3) + tan^-1(3/4)
=tan^-1(4/3+3/4)/(1–4/3×3/4)
=tan^-1(infinite)
=pi/2 , Answer
Answered by
1
Answer:
90
Step-by-step explanation:
2tan^-1(1/2)+sin^-1(3/5)=2(26.565) + 36.87 = 90
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