Question

2tan^245°+cos^230°-sin^260°​

Answer 1

Answer:

Step-by-step explanation:

tan 45 ° = 1

cos 30° = $\frac{\sqrt{3} }{2}$

sin 60° = $\frac{\sqrt{3} }{2}$

$tan^{2} 45$°=1

$cos^{2} 30$°=$\frac{3}{2}$

$sin^{2} 60$° = $\frac{3}{2}$

2 x $tan^{2}45$°+$cos^{2} 30$°-$sin^{2} 60$°

= 2 x 1 x $\frac{3}{2}$ x $\frac{3}{2}$

=2 x 1 x $\frac{9}{4}$

=$\frac{9}{2}$

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Answer 2

Answer:2

Step-by answer

$2Tan^{2} 45+cos^{2}30-sin^{2}60\\ 2(1)^{2}+(\sqrt{3}/2) ^{2} -(\sqrt{3}/2) ^{2}$

2+3/4-3/4=2