Question

2tan 45 degree+ cos 30 degree - sin 60 degree​

Answer 1

Given

$\tt \to2tan45^{ \circ} + cos30^{ \circ} - sin60^{ \circ}$

we have to simplify

We know

$\tt \to \: tan45^{ \circ} = 1$

$\tt \to \: cos30^{ \circ} = \dfrac{ \sqrt{3} }{2}$

$\tt \to \: sin60^{ \circ} = \dfrac{ \sqrt{3} }{2}$

Now put the value on

$\tt \to2tan45^{ \circ} + cos30^{ \circ} - sin60^{ \circ}$

$\tt \to \: 2 \times 1 + \dfrac{ \sqrt{3} }{2} - \dfrac{ \sqrt{3} }{2}$

$\tt \to \: 2 + \cancel{ \dfrac{ \sqrt{3} }{2}} - \cancel{ \dfrac{ \sqrt{3} }{2} }$

$\tt \to \: 2$

Answer

$\tt \to \: 2$

More Formula Of Trigonometric

$\tt \to \: sin(2x) = 2cos(x)sin(x)$

$\tt \to \: cos(2x) = cos {}^{2} x - sin {}^{2} x = 2cos {}^{2} x - 1$

$\tt \to \: tan(2x) = \dfrac{2tan(x)}{1 - tan(x)}$