2tan square thata= sec squar thita
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1
2 Tan²θ=sec²θ
2 sin²θ/cos²θ=1/cos²θ
sin²θ=1/2
sinθ=±1/√2
θ=π/4,π+π/4
2 sin²θ/cos²θ=1/cos²θ
sin²θ=1/2
sinθ=±1/√2
θ=π/4,π+π/4
Answered by
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2tan^2x=sec^2x
=sec^2x-2tan^2x=0
=1-tan^2x=0

=sec^2x-2tan^2x=0
=1-tan^2x=0
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