Question

2tan square thata= sec squar thita

Answer 1

2 Tan²θ=sec²θ
2 sin²θ/cos²θ=1/cos²θ
sin²θ=1/2
sinθ=±1/√2
θ=π/4,π+π/4

Answer 2

2tan^2x=sec^2x
=sec^2x-2tan^2x=0
=1-tan^2x=0

$n\pi - \frac{\pi}{4}$