Math, asked by rasif0907, 11 months ago

2tan30°cos60°÷1+tan²30°-tan²45°-1/2cos60°cot60°÷1-tan²30°​

Answers

Answered by shreyanshsinghk
0

Answer:

Step-by-step explanation:

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Answered by nishasingla6893
2

Answer:

2(1/√3) ×1/2÷1+(1/√3) ²-(1) ²-1/2(1/2) ×1/√3÷1-(1/√3) ²

2(1//√3) ×1/2÷1+1/3-1+1/4×1/√3÷1-(1/3)

Now, I will not do this sum

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