Math, asked by hpen67, 1 year ago

2tanx=3tany
tan(x-y)=?

Answers

Answered by mysticd
0
tan x =3/2 tany----(1)
tan(x-y)=(tanx-tany)/(1+tanxtany)

=(3/2tany-tany)/(1+3/2tany*tany)from (1)
=[(3tany-2tany)/2]/[(2+3tan^2y)/2]

=tany/(2+3tan^2y)
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