Math, asked by wwwannanyaanamika, 11 months ago

2u+3v=9uv 4u+av=21uv Solve by elemination method

Answers

Answered by panditsarthak004
0

Answer:

2u+3v=9uv---------1

4u+av=21uv--------2

divide eq1 and eq2 by uv

2/v+3/u=9----------3                let 1/u be y

4/v+a/u=21---------4                let 1/v be x

           

2x+3y=9-------------5

4x+ay=21------------6

multiplying eq5 by 2

4x+6y=18

4x+ay=21

------------------(changing signs while subtracting)

(-) (-)     (-)

    6y-a=-3

       

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