Question

2wires of same dimensions with resistivity rho 1and rho2 are connected in series , then their equivalent resistivity will be

Answer 1

parallel:rho(parallel)=(rho1)( rho2)/(rho1 + rho2) ... In series; Req=(rho1+ rho2)L/A =>Resistivity=(rho1+rho2) ... First we can start with calculating the equivalent ...

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