Question

(2x+1)² = 16 (Quadratic Equation to be solved using identities.)

Answer 1

Answer:

(2x+1)² = 16

4X^2 + 4X + 1 = 16

Step-by-step explanation:

Answer 2

Step-by-step explanation:

let (2x+1) be (a+b) ^2

2x=a,1=b

a^2+2ab+b^2=16

(2x)^2+2*2x*1+(1)^2=16

4x^2+4x+1=16

4x^2+4x=16-1

4x^2+4x=15