(2x+1)^2+(x+1)^2=6x+47 please solve this in quardic equation
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its +3 and -3...answer...plz check out
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lucky490:
this is right answers
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Heya !!!
(2X+1)² + (X+1)² = 6X +47
(2X)² + (1)² + 2 × 2X × 1 + X² + 1 + 2 × X × 1 = 6X +47
=>4X² + 1 + 4X + X² + 1 + 2X = 6X + 47
=> 4X² + X² + 4X + 2X -6X + 2 = 47
=> 5X² + 6X -6X = 47 - 2
=> 5X² = 45
=> X² = 45/5
=> X² = 9
=> X = ✓9 = +- 3
HOPE IT WILL HELP YOU....... :-)
(2X+1)² + (X+1)² = 6X +47
(2X)² + (1)² + 2 × 2X × 1 + X² + 1 + 2 × X × 1 = 6X +47
=>4X² + 1 + 4X + X² + 1 + 2X = 6X + 47
=> 4X² + X² + 4X + 2X -6X + 2 = 47
=> 5X² + 6X -6X = 47 - 2
=> 5X² = 45
=> X² = 45/5
=> X² = 9
=> X = ✓9 = +- 3
HOPE IT WILL HELP YOU....... :-)
ya that's great :
#:)
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