Question

( 2x+1 )^2 - ( x+3)^2​

Answer 1

Sorry for my answer but Brainliest me please please

Answer 2

$({2x + 1})^{2} - ({x + 3})^{2}$

$= 4 {x}^{2} + 4x + 1 - {x}^{2} - 6x - 9$

$= 3 {x}^{2} - 2x - 8$

It could have been a Quadratic equation if it had = 0.

Assuming it to be the Quadratic, we have

$3 {x}^{2} - 6x + 4x - 8 = 0$

$3x(x - 2) + 4(x - 2) = 0$

$(3x + 4)(x - 2) = 0$

x = 2, -4/3