Question

সমাধান করো : (2x+1)-
(2x+1)
2​

Answer 1

$\huge\red{\tt{\underline {Required\:Answer:}}}$

$(2x + 1) + \frac {3}{(2x + 1)} = 4 \\ \implies\frac {4 {x}^{2} + 4x + 1 + 3 } {2x + 1} = 4 \\\implies \frac {4( {x}^{2} + x + 1) }{2x + 1} = 4 \\\implies{x}^{2} + x + 1 = 2x + 1 \\\implies {x}^{2} + x - 2x = 1 -1 \\\implies {x}^{2} - x = 0 \\\implies x(x - 1) = 0$

হয়, x = 0 নতুবা, x = 1

∴ নির্ণেয় সমাধান : x = 0, 1

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Answer 2

দেওয়া আছে :-

• $\sf(2x + 1) +\sf \dfrac {3}{(2x + 1)} = 4$

খুঁজতে হবে :-

• Value of "X"

সমাধান :-

প্রশ্ন অনুসারে,

• $\sf(2x + 1) +\sf \dfrac {3}{(2x + 1)} = 4$

$\sf : \implies\sf\dfrac {4 {x}^{2} + 4x + 1 + 3 } {2x + 1} = 4$

$\sf:\implies\sf \dfrac {4( {x}^{2} + x + 1) }{2x + 1} = 4$

$\sf:\implies{x}^{2} + x + 1 = 2x + 1$

$\sf:\implies {x}^{2} + x - 2x = 1 -1$

$\sf:\implies {x}^{2} - x = 0$

$\sf:\implies x(x - 1) = 0$

তাহলে,

$:\implies{\underline{\boxed{\frak{\red{x = 0}}}}}\;\bigstar$

অথবা,

$\sf:\implies (x - 1) = 0$

$:\implies{\underline{\boxed{\frak{\red{x = 1}}}}}\;\bigstar$

$\boxed {\sf {\purple {সুতরাং , x \ এর \ মান \ হলো \ 1 \ or \ 0.}}}$

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