(2x+1) (2x-1) (4x²+ 1)
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Answer:
(2x+1) (2x-1) (4x²+1)
= (2x)²-1² (4x²+1)
= (4x²-1²) (4x²+1²)
= (4x²)² - 1²
= 16(x²)² - 1
16(x²)² = 1
(x²)² = 1/16
(x²) = √1/16
(x²) = 1/4
x = √1/4
x = 1/2
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