Question

(2x-1/2x)²-(2x+1/2x)(2x-1/2x)​

Answer 1

${\huge{\boxed{\tt{\color {red}{Answer❀✿°᭄}}}}}$

• Notice, expand the second term by multiplication,
• Notice, expand the second term by multiplication,2x(2x−1)−(2x+1)(2x−1)=0
• Notice, expand the second term by multiplication,2x(2x−1)−(2x+1)(2x−1)=0 2x(2x−1)–––––––––––−2x(2x−1)–––––––––––−(2x−1)=0
• Notice, expand the second term by multiplication,2x(2x−1)−(2x+1)(2x−1)=0 2x(2x−1)–––––––––––−2x(2x−1)–––––––––––−(2x−1)=0 −(2x−1)=0
• Notice, expand the second term by multiplication,2x(2x−1)−(2x+1)(2x−1)=0 2x(2x−1)–––––––––––−2x(2x−1)–––––––––––−(2x−1)=0 −(2x−1)=0 2x−1=0
• Notice, expand the second term by multiplication,2x(2x−1)−(2x+1)(2x−1)=0 2x(2x−1)–––––––––––−2x(2x−1)–––––––––––−(2x−1)=0 −(2x−1)=0 2x−1=0 2x=1

Answer 2

Step-by-step explanation:

multiplication,2x(2x−1)−(2x+1)(2x−1)=0 2x(2x−1)–––––––––––−2x(2x−1)–––––––––––−(2x−1)=0 −(2x−1)=0 2x−1=0

Notice, expand the second term by multiplication,2x(2x−1)−(2x+1)(2x−1)=0 2x(2x−1)–––––––––––−2x(2x−1)–––––––––––−(2x−1)=0 −(2x−1)=0 2x−1=0 2x=