Question

(2x-1/2y-3z) the whole square expand

Answer 1

Answer:

  (2x - 1/2y - 3z)^2 = [(2x - 1)^2/(2y - 3z)^2]

= [{(2x)^2 + 1^2 - 2(2x * 1)} / {(2y)^2 + (3z)^2 - 2(2y * 3z)}]

= [4x^2 + 1 - 4x] / [4y^2 + 9z^2 - 12yz]

= 4x^2 + 1 - 4x/4y^2 + 9z^2 - 12yz

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Answer 2

Answer:

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