Question

2x-1\3=1\6-x solve the equations and verify your result​

Answer 1

Given that

Let

LHS as left hand side

RHS as right hand side

$2x - \frac{1}{3} = \frac{1}{6} - x$

To solve and verify it

Solution

First we will solve this equation and calculate value of x

hence

$2x - \frac{1}{3} = \frac{1}{6} - x$

by cross multiplication of both sides

$\frac{6x - 3}{3} = \frac{1 - 6x}{6}$

swap 6 to left hand side and 3 to right hand side

then

$6(6x - 3) = 3(1 - 6x)$

by multiplication

$36x + 18x = 3 + 6$

by addition we get

$54x = 9$

hence x will be

$x = \frac{9}{54} = \frac{1}{6}$

To verify equation put x is lhs and rhs we get

$2 \times \frac{1}{6} - \frac{1}{3} = \frac{1}{6} - \frac{1}{6}$

by solving we get

$\frac{1}{3} - \frac{1}{3} = \frac{1}{6} - \frac{1}{6}$

$0 = 0$

hence verify that

LHS is equal to RHS.

Answer 2

2x-1/3=1/6-x

2x-1/3=1-6x/6(by taking LCM)

cross multiplication

6(2x-1)=3(1-6x)

12x-6=3-18x

12x+18x=3+6

30x=9

x=9/30

x= 0.3