Question

(2x+1)+3/2x+1=4 solve this​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$(2x + 1) + \frac{3}{2x + 1} = 4 \\ \\ = > \frac{ {(2x + 1)}^{2} + 3}{2x + 1} = 4 \\ \\ = > 4 {x}^{2} + 2x + 1 + 3 = 4(2x + 1) \: \: \: \: \: \: \: (cross \: multiplication) \\ \\ = > 4 {x}^{2} + 2x + 4 = 8x + 4 \\ = > 4 {x}^{2} + 2x + 4 - 4 - 8x = 0 \\ = > 4 {x}^{2} - 6x = 0 \\ = > 2x(2x - 3) = 0 \\ \\ either \: 2x = 0 \: \: \: \: \: \: \: \: \: \: or \: (2x - 3) = 0 \\ x = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: 2x = 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: x = \frac{3}{2}$

So, x = 0 or 3/2

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