(2x-1)÷3≥(3x-2)÷4-(2-x)÷5
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3
(2x−1)
≥
4
(3x−2)
−
5
(2−x)
⇒
3
(2x−1)
≥
20
5(3x−2)−4(2−x)
⇒
3
(2x−1)
≥
20
15x−10−8+4x
⇒
3
(2x−1)
≥
20
19x−18
⇒20(2x−1)≥3(19x−18)
⇒40x−20≥57x−54
⇒−20+54≥57x−40
⇒34≥17x
⇒2≥x
Thus, all real numbers x, which are less than or equal to 2, are the solution, of of the given inequality.
Hence, the solution set of the given inequality is (−∞,2]
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