Math, asked by adithyanthekkedath20, 1 month ago

(2x-1)÷3≥(3x-2)÷4-(2-x)÷5​

Answers

Answered by vikask29092010
1

Answer:

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I don't no the this sum

Answered by bhattvindhyavasini
0

Answer:

Solution

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3

(2x−1)

4

(3x−2)

5

(2−x)

3

(2x−1)

20

5(3x−2)−4(2−x)

3

(2x−1)

20

15x−10−8+4x

3

(2x−1)

20

19x−18

⇒20(2x−1)≥3(19x−18)

⇒40x−20≥57x−54

⇒−20+54≥57x−40

⇒34≥17x

⇒2≥x

Thus, all real numbers x, which are less than or equal to 2, are the solution, of of the given inequality.

Hence, the solution set of the given inequality is (−∞,2]

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