Math, asked by Akshita5581, 8 months ago

(2x-1)/3-(6x-2)/5=1/3 find the value of x​

Answers

Answered by vrundamin
3

Answer:

The value of x is x=-\frac{1}{2}x=−

2

1

Step-by-step explanation:

Given : Expression \frac{2x-1}{3}-\frac{6x-2}{5}=\frac{1}{3}

3

2x−1

5

6x−2

=

3

1

To find : Solve the expression ?

Solution :

Expression \frac{2x-1}{3}-\frac{6x-2}{5}=\frac{1}{3}

3

2x−1

5

6x−2

=

3

1

Taking LCM,

\frac{5(2x-1)-3(6x-2)}{15}=\frac{1}{3}

15

5(2x−1)−3(6x−2)

=

3

1

\frac{10x-5-18x+6}{15}=\frac{1}{3}

15

10x−5−18x+6

=

3

1

\frac{1-8x}{15}=\frac{1}{3}

15

1−8x

=

3

1

Cross multiply,

3(1-8x)=153(1−8x)=15

3-24x=153−24x=15

24x=-1224x=−12

x=-\frac{12}{24}x=−

24

12

x=-\frac{1}{2}x=−

2

1

Therefore, The value of x is x=-\frac{1}{2}x=−

2

1

Answered by priya9505
4

Answer:

X= -1/2

hope it helps.....

Attachments:
Similar questions