Question

2x + 1 /3 whole square minus x minus 1 divided 2 by whole square

Answer 1

$Please \: mark \:my \: answer \: as \: the \\ BRILLIANIST \\ ANSWER.$

=> ( 2x + 1/3 )² - ( x - 1/2 )²

=> Using a² - b² = (,a + b ) ( a - b )

=> ( 2x + 1/3 + x - 1/2 ) ( 2x + 1/3 - x + 1/2 )

=> ( x + 2/6 - 3/6 ) ( 3x + 2/6 + 3 /6 )

=> ( x -1/6 ) ( 3x + 5/6 )

$Hope \: it \: helps$

Answer 2

Answer:

$\text{The factorized form is }(2x+\frac{1}{3})^2-(x-\frac{1}{2})^2$

Step-by-step explanation:

Given the expression

$(2x+\frac{1}{3})^2-(x-\frac{1}{2})^2$

we have to solve the above expression.

By identity

$(a^2-b^2)=(a-b)(a+b)$

$(2x+\frac{1}{3})^2-(x-\frac{1}{2})^2$

Using above identity

$(2x+\frac{1}{3}-(x-\frac{1}{2}))(2x+\frac{1}{3}+(x-\frac{1}{2}))$

$(2x+\frac{1}{3}-x+\frac{1}{2})(2x+\frac{1}{3}+x-\frac{1}{2})$

$(x+\frac{5}{6})(3x-\frac{1}{6})$

which is the factorized form.